First slide

Application of integration

Question

The area of region between y = sinx and x–axis in the interval $[0, \frac{π}{2}]$ , will be :

Easy

A

1
B

0
C

2
D

4

Solution

$\int_{0}^{π / 2} \sin x d x = [- \cos x]_{0}^{π / 2} = 1$

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