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The area of region between y = sinx and x–axis in the interval $[0, \frac{π}{2}]$ , will be :

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detailed solution

Correct option is A

∫0π/2 sin⁡xdx=[−cos⁡x]0π/2=1

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The area of region between y = sinx and x–axis in the interval 0,π2, will be :

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The area of region between y = sinx and x–axis in the interval $[0, \frac{π}{2}]$ , will be :