Questions
In the arrangement of capacitors shown in Fig. 3.61, the capacitors are initially uncharged, and now are connected with switch S open. Find the potential of point b and the amount of charge flowing through the switch, when it is closed :
detailed solution
Correct option is C
When switch S is openTotal capacity of circuit = 4 μFTotal charge stored = 200 x 4 μC = 800 μCWhere switch S is closedIt is clear that potential of point b = 100 Vand charge flown through S = 200 + 100 = 300 μCTalk to our academic expert!
Similar Questions
Before connecting to the circuit shown in figure, all capacitors were uncharged. The circuit now is in steady state. Now the switch S is closed. During the time the steady state is reached again
Column - I | Column - II | ||
(i) | Charge on C1 | p. | increases |
(ii) | Charge on C2 | q. | decreases |
(iii) | Charge on C3 | r. | remains same |
(iv) | Charge on C4 | s. | becomes zero |
Now, match the given columns and select the correct option from the codes given below.
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