In the arrangement of capacitors shown in Fig. 3.61, the capacitors are initially uncharged, and now are connected with switch S open. Find the potential of point b and the amount of charge flowing through the switch, when it is closed :
When switch S is open
Total capacity of circuit = 4 μF
Total charge stored = 200 x 4 μC = 800 μC
Where switch S is closed
It is clear that potential of point b = 100 V
and charge flown through S = 200 + 100 = 300 μC