In the arrangement of capacitors shown in Fig. 3.61, the capacitors are initially uncharged, and now are connected with switch S open. Find the potential of point b and the amount of charge flowing through the switch, when it is closed :
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
66.7 V, 300 μC
b
66.7 V, 400 μC
c
100 V, 300 μC
d
133.3 V, 400 μC
answer is C.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
When switch S is openTotal capacity of circuit = 4 μFTotal charge stored = 200 x 4 μC = 800 μCWhere switch S is closedIt is clear that potential of point b = 100 Vand charge flown through S = 200 + 100 = 300 μC