Q.
In the arrangement shown, the block is released from rest from x = 0 (when the spring was in its natural length), on an incline having µ = 0.5x. The maximum elongation in the spring will be (in m) use g=10m/s2
see full answer
Start JEE / NEET / Foundation preparation at rupees 99/day !!
21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya
answer is 2.
(Unlock A.I Detailed Solution for FREE)
Ready to Test Your Skills?
Check your Performance Today with our Free Mock Test used by Toppers!
Take Free Test
Detailed Solution
Wg+Wf+WN+Wspring=ΔK ⇒(50sin37o)xm−∫0xm(0.5x)(50cos37o)dx+0−12kxm2=12m(vf2−vi2)At the point of max. elongation v = 0⇒30xm−10xm2−5xm2=0⇒30=10xm+5xm⇒15xm=30⇒xm=2m
Watch 3-min video & get full concept clarity