In the arrangement shown, the blocks A and B are oscillating horizontally without any relative motion between them. Blocks A and B have masses 2 kg and 1 kg respectively. Spring constant k=600 N/m. There is no friction between block A and the bottom surface but friction is there between A and B. If amplitude of oscillation is 10 cm, the maximum frictional force acting on B is

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Detailed Solution

ω=k/(M+m)Maximum pseudo force on block B =mω2A=mkA(M+m)∴ f=mkAM+m=1×600×0.1(2+1) N=20 N

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