First slide

Application of p-n junction diode rectifier

Question

In the arrangement shown, breakdown potential of the Zener diode is 90 volt. Then current through the $100 Ω$ resistor is

Moderate

A

50 mA
B

100 mA
C

200 mA
D

10 mA

Solution

$I = \frac{100 - v_{z}}{100} = \frac{100 - 90}{100} A = 100 mA$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App