In the arrangement shown, coefficient of friction between the block and the surface is 0.6 then
acceleration of the block is 1 m/s2
acceleration of the block is 0.5 m/s2
frictional force acting on the block is 12 N
frictional force acting on the block is 10 N
fmax=μN=μmg=0.6×2×10 N=12 N
since 10 N<fmax, the block will be in equilibrium
Hence frictional force acting on the block is 10 N.