Questions
In the arrangement shown, the end B of the rod of length ‘l’ is made to move with constant velocity V. Then velocity of its centre of mass when is
detailed solution
Correct option is D
O is the position of instantaneous centre of rotation. Then entire rod is rotating about O with angular velocity ω at that instantwhere ω = vBOB = vl sin θNow OA2 + OB2 = 2. AC2 + OC2⇒ l2 cos2θ + l2 sin2 θ = 2 l24 + OC2⇒ OC2 = l22 − l24 = l24 ⇒ OC = l2∴ vC = ω . OC = vl sin θ × l2 = v2 sin θWhen θ = 300, vC = v2 sin 300 = vSimilar Questions
Four solid spheres are made to move on a rough horizontal surface. Sphere P is given a spin and released. Sphere Q is given a forward linear velocity. Spheres R and S are given linear and rotational motions as shown in the figure. Directions of the friction force on spheres P, Q, R and S are respectively.
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