Questions
In the arrangement shown, the equivalent capacitance between points A and B is
a
4.5 µF
b
18 µF
c
2 µF
d
9 µF
detailed solution
Correct option is A
The given circuit is equivalent to one shown in the figure ∴CAb=9×99+9μF=4.5μF.Talk to our academic expert!
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Two capacitors C1 and C2 having capacitance respectively are connected as shown in the figure. Initially C1 has charge 4 and C2 is uncharged. After long time closing the switch S :
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