Questions
In the arrangement shown in figure, the capacitors are indentical. When S1 is closed and S2 is open, equivalent capacitance between A and B is 4µF. What will be the equivalent capacitor between A and B when S1 is open and S2 is closed?
detailed solution
Correct option is A
In the first case, CAB=2C×C2C+C=4⇒C=6µFIn the second case, C'AB=C+C2=32C=32×6µF=9µFTalk to our academic expert!
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Two capacitors C1 and C2 having capacitance respectively are connected as shown in the figure. Initially C1 has charge 4 and C2 is uncharged. After long time closing the switch S :
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