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Q.

In the arrangement shown in figure, the capacitors are indentical. When S1 is closed and S2 is open, equivalent capacitance between A and B is 4µF. What will be the equivalent capacitor between A and B when S1 is open and S2 is closed?

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a

9 µF

b

6 µF

c

12 µF

d

4.5 µF

answer is A.

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Detailed Solution

In the first case, CAB=2C×C2C+C=4⇒C=6µFIn the second case, C'AB=C+C2=32C=32×6µF=9µF

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