First slide

Application of Newtons laws

Question

In the arrangement shown in the figure, if the acceleration of B is $\vec{a}$ , then find the acceleration of A.

Difficult

A

$a \sin α$
B

$a \cot θ$
C

$a \tan θ$
D

$a (\sin α \cot θ + \cos α)$

Solution

Direction of acceleration of .B is along the fixed incline, and that of A is along horizontal towards left.
From diagram, acceleration of B is represented by $\vec{A B}$ while its horizontal and vertical components are shown by AO and OB ,respectively. Acceleration of A is represented by $\vec{A C}$
$\vec{O C} = a (\sin α \cot θ + \cos α)$

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