In the arrangement shown in the figure, if the acceleration of B is a→, then find the acceleration of A.
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a
asinα
b
acotθ
c
atanθ
d
a(sinαcotθ+cosα)
answer is D.
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Detailed Solution
Direction of acceleration of .B is along the fixed incline, and that of A is along horizontal towards left.From diagram, acceleration of B is represented by AB→ while its horizontal and vertical components are shown by AO and OB ,respectively. Acceleration of A is represented by AC→OC→=a(sinαcotθ+cosα)