In the arrangement shown in figure, image of light source O is obtained at the bottom of beaker containing water μ$$=43$$. The value of H is $$___$$ (given$$ that O is $$36cm$$ from pole of lens and mirror is at $$100$$ cm from $$lens)

Question

In the arrangement shown in figure, image of light source O is obtained at the bottom of beaker containing water μ$$=43$$. The value of H is $$___$$ (given$$ that O is $$36cm$$ from pole of lens and mirror is at $$100$$ cm from $$lens)

Infinity Learn · Accepted Answer

For lens  $$1v$$−$$1u=1f$$ ⇒$$1v$$−$$1-36=130$$ ⇒$$v=180cm$$ In absence of mirror, image should have formed at $$I1$$ , $$80$$ cm behind mirror. So, $$I1$$ will behave as virtual object and its real image should have formed at $$I2$$, $$80$$ cm vertically below principal axis. But, due to presence of water, real image is shifted to $$I3$$ , at bottom of beaker. Inside beaker, $$2020-x=43$$ ⇒$$x=5$$ cm Thus, $$H=80+x=85$$ cm

In the arrangement shown in figure, image of light source O is obtained at the bottom of beaker containing water $(μ = \frac{4}{3})$ . The value of H is ___ (given that O is 36cm from pole of lens and mirror is at 100 cm from lens)

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In the arrangement shown in figure, image of light source O is obtained at the bottom of beaker containing water μ=43. The value of H is ___ (given that O is 36cm from pole of lens and mirror is at 100 cm from lens)

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In the arrangement shown in figure, image of light source O is obtained at the bottom of beaker containing water $(μ = \frac{4}{3})$ . The value of H is ___ (given that O is 36cm from pole of lens and mirror is at 100 cm from lens)