Questions
In the arrangement shown in the figure pulleys A and B are massless and the thread is inextensible. Mass of pulley C is equal to m. If friction in all the pulleys is negligible, then
detailed solution
Correct option is D
FBD of Cmg−2T=mc ……(i)If we assume acceleration of A to be 'a'upwards; by constraint equation we get:−a−a+c+a+c=0⇒a=2cand for block A:2T=mA⋅a but as mA=0⇒T=0 so we get c=g and a=2g↑Talk to our academic expert!
Similar Questions
Figure shows two blocks, each of mass m. The system is released from rest. If accelerations of blocks
A and B at any instant (not initially) are a1 and a2, respectively, then
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