In the arrangement shown in figure sin⁡37∘=35

10gsin⁡37∘=10×10×0.6=60N                    4g=4×10=40N Since     60N>40NBlock of mass 10 kg has a tendency to move down the plane. Therefore force of friction on 10 kg is up the plane.μmgcos⁡θ=0.7×10×10×0.8=56N=F1 (say) Net pulling force:F2=(60−40)N=20NSince F2