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Q.

In the arrangement shown initially switch s is open. When switch s is closed,

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a

reading of voltmeter is halned

b

reading of voltmeter becomes 4 times the initial reading

c

power dissipated in left resistor becomes 4 times the initial power

d

power dissipated in the left resister is doubled

answer is C.

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Detailed Solution

When s is open, i = E/2R∴ reading of voltmeter = i R= E/2 .Initial power dissipated in the left resistor = i2R=E2R2R=E2/4R.When s is closed, reading of voltmeter = E. Power dissipated in left resistor = E2R.
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