In the arrangement shown, the pulleys are smooth and the strings are inextensible. Find the acceleration of block B in m/s2. Take g=10 m/s2
Let acceleration of B is a downwards using F.B.D. of A and B
2T−mg=ma2mg−T=ma⇒ T=mg−ma
From (i) and (ii), we get
2mg−2ma−mg=ma2mg=5ma2⇒a=2g5=4.00m/s2