Q.

in the arrangement shown, readings of ideal voltmeters V1, V2 and V3 are 20 volt, 50 volt and 60 volt respectively. then current flowing through the current carrying branch is

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a

5 A

b

2.5 A

c

1 A

d

0.5 A

answer is C.

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Detailed Solution

V1=iP,          V2=iQ+R      and    V3=iP+Q∴iR=V1+V2−V3⇒i=V1+V2−V3R=20+50−6010Amp  ⇒i=  1  A
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