Questions
in the arrangement shown, readings of ideal voltmeters V1, V2 and V3 are 20 volt, 50 volt and 60 volt respectively. then current flowing through the current carrying branch is
a
5 A
b
2.5 A
c
1 A
d
0.5 A
detailed solution
Correct option is C
V1=iP, V2=iQ+R and V3=iP+Q∴iR=V1+V2−V3⇒i=V1+V2−V3R=20+50−6010Amp ⇒i= 1 ATalk to our academic expert!
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