First slide

Work done by Diff type of forces

Question

In the arrangement shown, There is no friction between the 4 kg block and the floor and friction exists at the interface of 2kg and 4kg blocks. If the blocks A and B move together without any relative motion between them, find the work done by the force of friction on block A in 2 second

Moderate

A

Zero
B

128J
C

64J
D

32J

Solution

Accelaration of the system, $a = \frac{24}{2 + 4} m / s^{2} = 4 m / s^{2}$
Friction force acting on 2kg block, f = 2 x 4 n=8 N
Displacement of the system of blocks , $x = \frac{1}{2} \times 4 \times 2^{2} m = 8 m$
$∴$ Work done by the friction on A =f.x=8 x 8 J=64 J

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