An arrangement of three parallel straight wires placed perpendicular to plane of paper carrying same current ‘I’ along the same direction as shown in figure. Magnitude of force per unit length on the middle wire ‘B’ is given by

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2μ0I2πd

μ0I22πd

answer is C.

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Detailed Solution

Force between wires A and B = force between wires B and C ∴FBC=FAB=μoI2l2πd As F→AB⊥F→BC, net force on wire B, Fnet =2FBC=2μoI2l2πdFnet =μoI2l2πd or Fnet l=μoI22πd

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