Question

An arrow is shot into air. Its range is 200 m and its time of flight is 5 s. If g = 10 ms^-2, then horizontal component of velocity and the maximum height will be respectively

Moderate

Solution

Time of flight, $T = \frac{2 u_{y}}{g}$
$\Rightarrow u_{y} = \frac{g T}{2} = 25 {ms}^{- 1}$
$Now, H = \frac{u_{y}^{2}}{2 g} = \frac{(25)^{2}}{20} = 31.25 m$
Further, $R = u_{x} T$
$\Rightarrow u_{x} = \frac{R}{T} = 40 {ms}^{- 1}$

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