An artificial radioactive decay series begins with unstable94Pu241 . The stable nuclide obtained after eight α -decays and five β -decays is

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83Br209

82Pb209

82Se205

82Mg201

answer is A.

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Detailed Solution

Decrease in mass no.=8×4+5×0=32 Decrease in charge no.=8×2−5×1=11 Therefore (a) is the right choice.

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