Questions
Assertion The maximum height of projectile is always 25% of the maximum range.
Reason For maximum range, projectile should be projected at 90°.
detailed solution
Correct option is C
To obtain maximum range, angle of projection must be 45°, i.e., θ = 45°.Rmax=u2sin2×45°g=u2g∵ Hmax=u2sin245°2g=u24g=Rmax4So, Hmax is 25 % of RmaxTalk to our academic expert!
Similar Questions
A ball is thrown with a velocity of u making an angle with the horizontal. Its velocity vector normal to initial vector (u) after a time interval of
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
