First slide
Projection Under uniform Acceleration
Question

Assertion : The maximum horizontal range of projectile is proportional to square of velocity.

Reason : The maximum horizontal range of projectile is equal to maximum height attained by projectile.
 

Moderate
Solution

= u2sin2θg

Rmax= u2g    where θ = 450

Rmax  u2

Height H = u2sin2θ2g

  Hmax = u22g  when θ = 900

It is clear that Hmax= Rmax2

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