Assertion: In simple harmonic motion, the velocity is maximum when acceleration is minimum
Reason: Displacement and velocity of SHM. differ is phase by $\frac{π}{2}$ .

Easy

A

If both statement I and statement II are true and statement II is the correct explanation of statement I.
B

If both statement I and statement II are true but statement II is not the correct explanation of statement I.
C

If statement I is true but statement II is false
D

If both statement I and statement II are false

Solution

$x = a \sin ωt and v = \frac{dx}{dt} = aω \cos ωt$
phase difference between ‘x’ and ‘a’ is $\frac{π}{2}$ .

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

SCAN ME