Assume that the number of hole – electron pair in an intrinsic semiconductor is proportional to e△E2kT . Here, △E= energy . gap and k=8.62×10−5eV/kelvin. The energy gap for silicon is 1.1 eV. The ratio of electron hole pairs at 300 K and 400 K is e−x . Find x

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answer is 0005.32.

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Detailed Solution

T1=300KT2=400K∴ratio=e−△E/2kT1e−△E/2kT2=e-△E2kT1+△E2kT2=e-△E2k[1T1−1T2]=e-△E2k[1300−1400]=e-1.1ev2×8.62×10−5ev[4-31200]=e-1.117.24[11200×10−5]=e-1101724×12×10−3 = e-1100001724×12 ==e−5.32

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