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Q.

Assume that the number of hole-electron pair in an intrinsic semiconductor is proportional to e−ΔE/2KT . Here ΔE = energy gap and k=8.62×10−5 eV / kelvin The energy gap for silicon is 1.1eV. The ratio of electron hole pairs at 300K and 400 K is :

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a

e-5.31

b

e-5

c

e

d

e2

answer is A.

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Detailed Solution

N1N2=e−ΔE/2KT1e−ΔE/2KT2=eΔE2K1T2−1T1=1.1e2×8.62×10−51400−1300
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