Assuming that the atmosphere has the same density anywhere as at sea level (ρ = 1.3 kgm-3) and 9 to be constant (g = 10 ms-2). What should be the approximate height of atmosphere? (ρ0 = 1.01 X 105 Nm-2)

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6 km

8 km

12 km

18 km

answer is B.

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Detailed Solution

1 atmosphere =1.01×105Nm−2=ρgh∴ h=1.01×1051.3×10=7769m≈8km

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