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Questions  

Assuming that the electronic charge is 1.6 x 10-19 coulombs, the number of electrons passing through a section of wire per sec, when the wire carries a current of one ampere is :

a
0.625 x 1019
b
1.6 x 10-19
c
1.6 x 1019
d
0.627 x 10-17

detailed solution

Correct option is A

I=∆q∆t⇒I=net⇒n=Ite=111.6 x 10-19=6.25 x 1018

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