Assuming that the gravitational potential energy of an object at infinity is zero, the change in potential energy (final – initial) of an object of mass m, when taken to a height h from the surface of earth (of radius R), is given by,

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GMmR+h

-GMmR+h

GMmhR(R+h)

mgh

answer is C.

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Detailed Solution

(P.E)A=-GMmR(P.E)B=-GMmR+h∴ ΔU=(P.E)B-(P.E)A=- GMm R+h+ GMm R= GMmh (R)(R+h)

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