An astronomical telescope has an angular magnification of magnitude 5 for distant objects. The separation between the objective and the eye piece is 36 cm and the final image is formed at infinity. The focal length fo of the objective and the focal length fe of the eye piece are

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fo=45cm and fe=−9cm

fo=7.2cm and fe=5cm

fo=50cm and fe=10cm

fo=30cm and fe=6cm

answer is D.

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Detailed Solution

In this case |m|=fofe=5----(i) and length of telescope =f0+fe=36---(ii) Solving (i) and (ii), we get fe=6cm,f0=30cm

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