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An astronomical telescope has an angular magnification of magnitude 5 for distant objects. The seperation between the objective and the eye piece is 36 cm and the final image is formed at infinity. The focal length f0 of the objective and the focal length fe of the eye piece are
detailed solution
Correct option is D
m= f0fe⇒5=f0fe------(1) L= f0+fe⇒36=f0+fe----(2) Given From (1) & (2)f0 = 30cm, fe = 6cmTalk to our academic expert!
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