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An astronomical telescope has an angular magnification of magnitude 5 for distant objects. The separation between the objective and the eye-piece is 36 cm and the final image is formed at infinity. The focal length $f_{0}$ of the objective and $f_{e}$ of the eye-piece are :

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f0 = 45 cm and fe =-9 cm

f0 = 50 cm and fe = 10 cm

f0 = 7.2 cm and fe = 5cm

f0 =30 cm and fe = 6cm

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detailed solution

Correct option is D

f0+fe=36f0fe=5f0=5e5fe+fe=36fe=6f0=30

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An astronomical telescope has an angular magnification of magnitude 5 for distant objects. The separation between the objective and the eye-piece is 36 cm and the final image is formed at infinity. The focal length f0 of the objective and fe of the eye-piece are :

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Ready to Test Your Skills?

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An astronomical telescope has an angular magnification of magnitude 5 for distant objects. The separation between the objective and the eye-piece is 36 cm and the final image is formed at infinity. The focal length $f_{0}$ of the objective and $f_{e}$ of the eye-piece are :