Q.

An astronomical telescope has objective and eyepiece of focal lengths 40cm and 4cm respectively. To view an object 200cm away from the objective, the lenses must be separated by a distance

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a

50 cm

b

54 cm

c

37.3 cm

d

46 cm

answer is B.

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Detailed Solution

Here fo=40cm, fe=4cmTube length L= Distance between lenses = vo+fe For objective lens,uo=-200 cm, vo=?1vo-1u0=1fo or 1vo-1-200=140 or  1vo=140-1200=4200 ∴ vo=50 cm∴L=50+4=54 cm
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