In an astronomical telescope in normal adjustment, straight black line of length L is drawn on the objective. The eye piece forms a real image of this line. The length of this image is l. The magnification of the telescope is
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a
Ll
b
Ll+1
c
Ll-1
d
L+1l-1
answer is A.
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Detailed Solution
veue=1L and ue=f0+fe 1fe=1ve-1ue 1fe=1ve-1-f0+fe 1ve=1fe-1f0+fe=f0+fe-fef0+fefe=f0fef0+fe 1L=fef0+fef0f0+fe=fef0magnification of telescope = f0fe=Ll