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Questions  

The audio signal voltage is given by Vm=2sin12π×103t . The band width and LSB if carrier wave has a frequency 3.14×106rad/s

a
12kHz ; 494kHz
b
6kHz ; 313kHz
c
6kHz ; 494kHz
d
18kHz ; 494kHz

detailed solution

Correct option is A

Given  : Vm=2sin12π×103t  Comparing with Vm=V0sinwmt   we get,  wm=12π×103 ⇒2πfm=12π×103 ⇒fm=6000Hz=6kHz  Also,  it is given that wc=2πfc=3.14×106 rad/s ⇒2πfc=π×106 ⇒fc=5×105Hz=500kHz  Now,  Band width  = (fc+fm)−(fc−fm)                                   =2fm=12kHz  and LSB = fc−fm = 500 - 6 = 494 kHz

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A message signal of frequency 10 kHz and peak voltage of 10 volts is used to modulate a carrier of frequency 1 MHz and peak voltage of 20 volts. The side bands are 1010 kHz and______________kHz.


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