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Q.

An automobile spring extends 0.2 m for 5000 N load. The ratio of potential energy stored in the spring when it has been compressed by 0.2 m to the potential energy stored in a 10 μF capacitor at a potential difference of 10,000 V is

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a

2

b

1/2

c

1

d

1/4

answer is C.

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Detailed Solution

For spring, F = k x∴ 5000=k×0.2 or k=25000N/mNow ( Potential energy )spring ( Potential energy )capacitor =12kx212CV2=12×25000×(0⋅2)212×10×10−6×(104)2=1

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An automobile spring extends 0.2 m for 5000 N load. The ratio of potential energy stored in the spring when it has been compressed by 0.2 m to the potential energy stored in a 10 μF capacitor at a potential difference of 10,000 V is