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Q.

An automobile travelling with a speed of 60 km/h, can brake to stop within a distance of 2o m. If the car is going twice as fast, i.e., .120 km/h, the stopping distance will be

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a

20 m

b

40 m

c

60 m

d

80 m

answer is D.

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Detailed Solution

Here, u -60 km/h = (60 x 5)/18 = 50/3 m/sFrom equation, v2 = u2 -2aswe have 0=5032−2a×20or a=12518m/s2when u′=2u=2×(50/3)=(100/3)m/sthen, 0=10032−2×12518×sor s=80m
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