The average degrees of freedom per molecule for a gas are 6. The gas performs 25 J of work when it expands at constant pressure. The heat absorbed by gas is
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a
75 J
b
100 J
c
150 J
d
125 J
answer is B.
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Detailed Solution
As f = 6 (given), therefore γ=1+2f=1+26=43Fraction of energy given for external work ΔWΔQ=1−1γ⇒25ΔQ=1−14/3=1−34=14⇒ Q=25×4=100J