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Q.

The average degrees of freedom per molecule for a gas are 6. The gas performs 25 J of work when it expands at constant pressure. The heat absorbed by gas is

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a

75 J

b

100 J

c

150 J

d

125 J

answer is B.

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Detailed Solution

As f = 6 (given), therefore   γ=1+2f=1+26=43Fraction of energy given for external work    ΔWΔQ=1−1γ⇒25ΔQ=1−14/3=1−34=14⇒ Q=25×4=100J
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