The average degrees of freedom per molecule of a gas are 6. The gas performs 25J of work when expands at constant pressure. The heat absorbed by the gas is

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75 J

100 J

150 J

125 J

answer is B.

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Detailed Solution

r for the gas. 1+2f=γ;1+26⇒γ=43At constant pressure 1-1γ past of heat = workQ4→25JQ→100J

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