Questions
The average degrees of freedom per molecule of a gas are 6. The gas performs 25J of work when expands at constant pressure. The heat absorbed by the gas is
detailed solution
Correct option is B
r for the gas. 1+2f=γ;1+26⇒γ=43At constant pressure 1-1γ past of heat = workQ4→25JQ→100JTalk to our academic expert!
Similar Questions
One mole of an ideal monoatomic gas is heated from state point A to state point C according to the process A-B-C as shown in figure. Then total heat supplied to the gas is
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests