First slide

Heat given

Question

The average degrees of freedom per molecule of a gas are 6. The gas performs 25J of work when expands at constant pressure. The heat absorbed by the gas is

Easy

A

75 J
B

100 J
C

150 J
D

125 J

Solution

r for the gas. $1 + \frac{2}{f} = γ; 1 + \frac{2}{6} \Rightarrow γ = \frac{4}{3}$
At constant pressure $(1 - \frac{1}{γ})$ past of heat = work
$\frac{Q}{4} \to 25 J$
$Q \to 100 J$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App