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Q.

The average e.m.f. induced in a coil in which the current changes from 2 amperes to 4 amperes in 0.05 seconds is 8 volts. What is the self-inductance of the coil?

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a

0.1 H

b

0.2 H

c

0.4 H

d

0.8 H

answer is B.

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Detailed Solution

e=-Ldidt⇒8=L(4-2)0.05⇒L=0.2H
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