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An average induced e.m.f. of 1V appears in a coil when the current in it is changed from 10A in one direction to 10 A in opposite direction in 0.5 sec. Self-inductance of the coil is

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a

25 mH

b

50 mH

c

75 mH

d

100 mH

answer is A.

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Detailed Solution

|e| =Ldidt⇒1=L×10−−100.5⇒L=25mH

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