First slide

Measurement

Question

The Average life of an Indian is 56years. Find the number of times the human heart beats in the life of an Indian, if the heart beats once in 0.8 Second

Moderate

A

$4.4 \times 10^{9} t i m e s$
B

$2.2 \times 10^{9} t i m e s$
C

$1.1 \times 10^{9} t i m e s$
D

$3.3 \times 10^{9} t i m e s$

Solution

$A v e r g e l i f e o f a n I n d i a n = 56 y e a r s = 56 \times 365 \times 24 \times 60 \times 60 S e c o n d P e r i o d o f o n e h e a r t b e a t = 0.8 S e c . T o t a l n u m b e r o f b e a t s i n 56 y e a r s = \frac{A v e r g e l i f e}{P e r i o d o f o n e h e a r t b e a t} = \frac{56 \times 365 \times 24 \times 60 \times 60}{0.8} = 2.2075 x 10^{9} t i m e s$

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