Questions
Average torque on a projectile of mass m (initial speed u and angle of projection ) between initial and final positions P and Q as shown in figure, about the point of projection is:
detailed solution
Correct option is A
τav→.∆t = ∆L ------(i) Here ∆t = time of flight = 2u sin θgChange in angular momentum about point of projection (initially it is zero)|∆L→| = |L→f-Li→| = (mu sin θ) Range = (mu sin θ)(u2 sin 2θ)g = mu3sin θ sin2θgNow |τ→av| = |∆L→∆t| = mu3sin θ sin 2θg×g2u sin θ = mu2 sin 2θ2Similar Questions
A disc can rotate about an axis passing through its centre and perpendicular to the plane of the disc. Initially the disc is stationary and its moment of inertia about the axis is 4 Kg-m2. A torque is applied on the disc which varies with time according to the graph shown in figure. Then angular velocity of the disc at the end of 6th second is
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