Average torque on a projectile of mass m (initial$$ speed u and angle of projection θ$$) between initial and final positions P and Q as shown in figure, about the point of projection is:

Question

Average torque on a projectile of mass m (initial$$ speed u and angle of projection θ$$) between initial and final positions P and Q as shown in figure, about the point of projection is:

Infinity Learn · Accepted Answer

τav→.∆t $$=$$ ∆L $$------(i)$$ Here ∆t $$=$$ time of flight $$=$$ $$2u$$ $$sin$$ θgChange in angular momentum about point of projection (initially$$ it is $$zero)|∆L→| $$=$$ |L→$$f-Li$$→| $$=$$ (mu$$ $$sin$$ θ$$) Range         $$=$$ $$(mu$$ $$sin$$ θ$$)(u2$$ $$sin$$ $$2$$θ$$)g$$ $$=$$ $$mu3sin$$ θ $$sin2$$θgNow |τ→av| $$=$$ |∆L→∆t| $$=$$ $$mu3sin$$ θ $$sin$$ $$2$$θg×$$g2u$$ $$sin$$ θ         $$=$$ $$mu2$$ $$sin$$ $$2$$θ$$2$$

Average torque on a projectile of mass m (initial speed u and angle of projection $θ$ ) between initial and final positions P and Q as shown in figure, about the point of projection is:

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Average torque on a projectile of mass m (initial speed u and angle of projection θ) between initial and final positions P and Q as shown in figure, about the point of projection is:

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Average torque on a projectile of mass m (initial speed u and angle of projection $θ$ ) between initial and final positions P and Q as shown in figure, about the point of projection is: