The average translational energy and the rms speed of molecules of a sample of oxygen gas at 300 K are 6.21×10−21J and 484 ms-1 respectively. The corresponding values at 600 K are nearly (assuming ideal gas behaviour)

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12.42×10−21J,968ms−1

8.78×10−21J,684ms−1

6.21×10−21J,968ms−1

12.42×10−21J,684ms−1

answer is D.

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Detailed Solution

E∝T and vrms∝T. Hence at 600 K,E2E1=T2T1⇒E=6.21×10−21×600300 =12.42×10−21Jand v2v1=T2T1 vrms=484×600300≃684ms−1which is choice (d).

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