Questions
The average velocity of a body moving with uniform acceleration after travelling a distance of 3.06 m is 0.34 ms-1. If the change in velocity of the body is 0.18 ms-1 during this time, its uniform acceleration is
detailed solution
Correct option is B
Given vav=v+u2=0.34 ms−1 and v−u=0.18 ms−1Solving these two equations, we getu=0.25 ms−1, v=0.43 ms−1. Given s=3.06 mNow use v2−u2=2as to find a=0.02 ms−2Talk to our academic expert!
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An object, moving with a speed of 6.25 m/s, is declerated at a rate given by, where v is the instantaneous speed. The time taken by the
object, to come to rest would be
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