Average Acceleration

Question

The average velocity of a body moving with uniform acceleration after travelling a distance of 3.06 m is 0.34 ms^{-1}. If the change in velocity of the body is 0.18 ms^{-1} during this time, its uniform acceleration is

Easy

Solution

$\text{Given}{v}_{av}=\frac{v+u}{2}=0.34\text{and}v-u=0.18\phantom{\rule{0ex}{0ex}}Solvingthesetwoequations,weget\phantom{\rule{0ex}{0ex}}u=0.25{ms}^{-1},v=0.43{ms}^{-1}\phantom{\rule{0ex}{0ex}}\text{Given}s=3.06m\phantom{\rule{0ex}{0ex}}\text{Now use}{v}^{2}-{u}^{2}=\text{las to find}a=0.02{ms}^{-2}$

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