The average velocity of a body moving with uniform acceleration after travelling a distance of 3.06 m is 0.34 ms-1. If the change in velocity of the body is 0.18 ms-1 during this time, its uniform acceleration is

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0.01 ms-2

0.02 ms-2

0.03 ms-2

0.04 ms-2

answer is B.

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Detailed Solution

Given vav=v+u2=0.34 and v-u=0.18 Solving these two equations, we get u=0.25 ms-1,v=0.43 ms-1 Given s=3.06 m Now use v2-u2= las to find a=0.02 ms-2

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