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Q.

The average velocity of a body moving with uniform acceleration after travelling a distance of 3.06 m is 0.34 m s-1. If the change in velocity of the body is 0.18 m s-1 during this time, its uniform acceleration is

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a

0.01 ms-2

b

0.02 ms-2

c

0.03 ms-2

d

0.04 ms-2

answer is B.

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Detailed Solution

Given vav=v+u2=0.34 and v−u=0.18Solving these two equations, we get        u=0.25ms−1,v=0.43ms−1. Given s=3.06mNow use v2−u2=2as to find a=0.02ms−2.
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