First slide

Rectilinear Motion

Question

The average velocity of a body moving with uniform acceleration after travelling a distance of 3.06 m is 0.34 ms^-1. If the change in velocity of the body is 0.18 ms^-1 during this time, its uniform acceleration is

Moderate

A

$0.01 {ms}^{- 2}$
B

$0.02 {ms}^{- 2}$
C

$0.03 {ms}^{- 2}$
D

$0.04 {ms}^{- 2}$

Solution

$Given v_{av} = \frac{v + u}{2} = 0.34 and v - u = 0.18$
Solving these two equations, we get
$\begin{array}{l} u = 0.25 {ms}^{- 1}, v = 0.43 {ms}^{- 1} . Given s = 3.06 m \\ Now use v^{2} - u^{2} = 2 a s to find a = 0.02 {ms}^{- 2} . \end{array}$

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