A bag of sand of mass m is suspended by a rope. A bullet of mass m20 is fired at it with a velocity v and gets embedded into it. The velocity of the bag finally is
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a
v20×21
b
20v21
c
v20
d
v21
answer is D.
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Detailed Solution
Applying law of conservation of momentum.Momentum of the bullet = Momentum of sand – bullet system.m20v=(m+m20)V'=2120mV'