Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

A bag of sand of mass M is suspended by a string. A bullet of mass m is fired at it with velocity v and gets embedded into it. The loss of kinetic energy in this process is

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

12mv2

b

12mv2×1M+m

c

12mv2×Mm

d

12mv2MM+m

answer is D.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Initial kinetic energy of bullet = 12mv2After inelastic collision system moves with velocity V By the conservation of momentum mv+0=(m+M) V⇒V=mvm+MKinetic energy of system =  12(m+M) V2=  12(m+M) mvm+M2Loss of kinetic energy =  12mv2−12(m+M) mvm+M2= 12mv2Mm+M
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon
personalised 1:1 online tutoring