Balancing length of a potentiometer wire of a cell of emf 20 volt is 80 cm. What will be the balancing length of a cell of emf 15 volt in the same potentiometer wire?

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65 cm

55 cm

60 cm

70 cm

answer is C.

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Detailed Solution

E2E1=l2l1⇒l2=80×1520cm=60 cm

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