Questions
Balancing length of a potentiometer wire of a cell of emf 20 volt is 80 cm. What will be the balancing length of a cell of emf 15 volt in the same potentiometer wire?
detailed solution
Correct option is C
E2E1=l2l1⇒l2=80×1520cm=60 cmTalk to our academic expert!
Similar Questions
A cell of resistance and emf 10 volt is connected to a uniform wire of length 500 cm and resistance 3 ohm. The potential gradient in the wire is
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